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Find If A File Is Executable And Return Full Path To It
def find_executable(executable, path=None):
"""Try to find 'executable' in the directories listed in 'path' (a
string listing directories separated by 'os.pathsep'; defaults to
os.environ['PATH']). Returns the complete filename or None if not
found
"""
if path is None:
path = os.environ['PATH']
paths = path.split(os.pathsep)
extlist = ['']
if os.name == 'os2':
(base, ext) = os.path.splitext(executable)
# executable files on OS/2 can have an arbitrary extension, but
# .exe is automatically appended if no dot is present in the name
if not ext:
executable = executable + ".exe"
elif sys.platform == 'win32':
pathext = os.environ['PATHEXT'].lower().split(os.pathsep)
(base, ext) = os.path.splitext(executable)
if ext.lower() not in pathext:
extlist = pathext
for ext in extlist:
execname = executable + ext
if os.path.isfile(execname):
return execname
else:
for p in paths:
f = os.path.join(p, execname)
if os.path.isfile(f):
return f
else:
return None





