Partitioning An Array With Array#collect_every And Array#subdivide

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        Array#collect_every is taken from: 

http://redhanded.hobix.com/bits/matchingIntoMultipleAssignment.html

Author: Ezra Zygmuntowicz (in the comments)

# ---------------------------------------------------------------------------
# collect_every(n [,fill=false[,offset=0]])                  => an array
# collect_every(n [,fill=false[,offset=0]]) {|item| block}   => an_array
# ---------------------------------------------------------------------------
# If a block is given, it invokes the block passing in an array of n elements.
# The last array passed may not contain n elements if size % 2 does not equal
# zero. If no block is given, it returns an array containing the collections.
#
# If the optional argument fill is set to true, the empty spaces will be
# filled with nils. The optional argument offset allows the collection to 
# start at that index in the array.
#
# a = (1..10).to_a
# a.collect_every(5)               #=> [[1, 2, 3, 4, 5], [6, 7, 8, 9, 10]]
# a.collect_every(5) {|x| p x}     #=> [1, 2, 3, 4, 5]
#                                      [6, 7, 8, 9, 10]
# b = (1..7).to_a
# b.collect_every(3)               #=> [[1, 2, 3], [4, 5, 6], [7]]
# b.collect_every(3,true)          #=> [[1, 2, 3], [4, 5, 6], [7,nil,nil]]
# b.collect_every(3,true,1)        #=> [[2, 3, 4], [5, 6, 7]]


class Array

 def collect_every(n, fill=false, offset = 0)

  if block_given?
     while  offset < size
          ret = []

          if fill
             n.times do |x| 
                  if offset + x > size - 1 then ret << nil 
                  else  ret << self[offset + x] end
             end
          else
             n.times { |x| ret << self[offset + x] unless offset + x > size - 1}
          end 

          offset += n
          yield ret
          ret = nil
     end   

  else

   ret = []
   while  offset < size
     ret << []
     if fill
         n.times do |x|  
            if offset + x > size - 1 then ret.last << nil
            else ret.last << self[offset + x]; end
         end
     else
         n.times { |x| ret.last << self[offset + x] unless offset + x > size - 1 }
     end

     offset += n
   end
   return ret

  end 

 end
end


a = (1..10).to_a
puts a.collect_every(5).inspect                     #->  [[1, 2, 3, 4, 5], [6, 7, 8, 9, 10]]
a.collect_every(5) { |x| puts x.inspect }         #->  [1, 2, 3, 4, 5] and [6, 7, 8, 9, 10]
puts a.collect_every(3, true).inspect             #->  [[1, 2, 3], [4, 5, 6], [7, 8, 9], [10, nil, nil]]
puts a.collect_every(3, true,1).inspect          #->  [[2, 3, 4], [5, 6, 7], [8, 9, 10]]
puts a.collect_every(3, true,4).inspect          #->  [[5, 6, 7], [8, 9, 10]]

puts a.inspect                                              #->  [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]



# ------------------------------------------------------------------------



class Array

 def subdivide(n)
   return self if n <= 0 || n >= self.size
   result = []
   max_subarray_size = n - 1

     while self.size > 0
       result << self.slice!(0..max_subarray_size)
     end

   result
 end

end

a = ('a'..'g').to_a
b = a.subdivide(3)

puts b.inspect       #->  [["a", "b", "c"], ["d", "e", "f"], ["g"]]
puts a.inspect       #->  [] 

Tags:
• Array
• divide
• partition
• Ruby